(1/2m^2)=(1/m)-(1/2)

Simple and best practice solution for (1/2m^2)=(1/m)-(1/2) equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for (1/2m^2)=(1/m)-(1/2) equation: 


D( m )

m = 0

m = 0

m = 0

m in (-oo:0) U (0:+oo)

(1/2)*m^2 = 1/m-(1/2) // - 1/m-(1/2)

(1/2)*m^2-(1/m)+1/2 = 0

(1/2)*m^2-m^-1+1/2 = 0

1/2*m^2-1*m^-1+1/2*m^0 = 0

(1/2*m^3+1/2*m^1-1*m^0)/(m^1) = 0 // * m^2

m^1*(1/2*m^3+1/2*m^1-1*m^0) = 0

m^1

(1/2)*m^3+(1/2)*m-1 = 0

(1/2)*m^3+(1/2)*m-1 = 0 // * 0

{ 1, -1, 2, -2 }

1

m = 1

m^3+m-2 = 0

1

m-1

m^2+m+2

m^3+m-2

m-1

m^2-m^3

m^2+m-2

m-m^2

2*m-2

2-2*m

0

m^2+m+2 = 0

DELTA = 1^2-(1*2*4)

DELTA = -7

DELTA < 0

m in { 1} 

m = 1

See similar equations:

| 7(2x-9)=2(3x-8) | | -1/4x+1/3 | | 12-2(x+1)=2x+2 | | x^4-8x^3+26x^2-40x+25=0 | | 3(2+3x)=4(3+2x) | | -7x^2-77x-126=0 | | a^2-20a-1056=0 | | 6(x+1)=3(x+1)+x+5 | | x^2-6+11=0 | | 2(x+1)+3(x+1)=25 | | ((k+4)/4)+((k-1)/4)=(k+4)/4k | | (k+4/4)+(k-1/4)=k+4/4k | | 3(2x+1)+x=4x+27 | | 4d^2-8d-88=8 | | -4y+12=2(y+3) | | 2(x+5)+x=5x-10 | | 3x+17y=29 | | x+30=2(x+7)+3x | | -7=7+2w | | -3y-0.4=0.1x | | 6+x(6)=4+x(4) | | 4d^2-8d-88=0 | | 5(x+5)+3(x-3)=48 | | 9(5g+6)/2 | | 3(x-4)+x=2(x+1) | | 3(2x+1)-4x=2(x+5) | | 3x-2(x-4)=x+8 | | 2(1-x)=3x-8 | | 11x+27+5x+23=360 | | 7b-7=2b+13 | | 11x+27=5x+23 | | -7x-2y=-11 |

Equations solver categories